How do you find the derivative of #y=5/(2x^2)#?

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Answer 1 · 2017-12-14T06:49:54

# (dy)/(dx) = -5/(x^3) #

We must use the pwer rule:

#d/(dx) alphax^n = alphanx^(n-1) #

So we can write #5/(2x^2)# as # 5/2 x^-2 #

Now applying the rule:

#=> (dy)/(dx) = -2* 5/2 x^(-2-1) #

#=> -5x^-3 #

#=> -5/(x^3) #