How do you find the derivative of #y=(9x^2+1)/(x^2+7)#?
1 Answer
Dec 15, 2015
Simplify, then use the power rule and chain rule to find:
#(dy)/(dx) = (124x)/(x^2+7)^2#
Explanation:
First simplify:
#y=(9x^2+1)/(x^2+7)=(9(x^2+7)-62)/(x^2+7)=9-62(x^2+7)^(-1)#
Then use the power rule and chain rule to find:
#(dy)/(dx) = 2x*62(x^2+7)^-2 = (124x)/(x^2+7)^2#