How do you find the derivative of y=(cosx)(tanx)y=(cosx)(tanx)? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Shwetank Mauria Jun 15, 2016 (dy)/(dx)=cosxdydx=cosx Explanation: As y=cosx xxtanx=cosx xxsinx/cosx=sinxy=cosx×tanx=cosx×sinxcosx=sinx Hence (dy)/(dx)=cosxdydx=cosx Answer link Related questions What is the derivative of y=cos(x)y=cos(x) ? What is the derivative of y=tan(x)y=tan(x) ? How do you find the 108th derivative of y=cos(x)y=cos(x) ? How do you find the derivative of y=cos(x)y=cos(x) from first principle? How do you find the derivative of y=cos(x^2)y=cos(x2) ? How do you find the derivative of y=e^x cos(x)y=excos(x) ? How do you find the derivative of y=x^cos(x)y=xcos(x)? How do you find the second derivative of y=cos(x^2)y=cos(x2) ? How do you find the 50th derivative of y=cos(x)y=cos(x) ? How do you find the derivative of y=cos(x^2)y=cos(x2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 3780 views around the world You can reuse this answer Creative Commons License