How do you find the derivative of #y=(e^x+e^-x)/4#?

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Answer 1 · 2017-05-24T14:05:27

# dy/dx = (e^x-e^(-x))/4 = 1/2sinhx #

We have:

# y = (e^x+e^(-x))/4 #

Differentiating directly:

# dy/dx = (e^x-e^(-x))/4 #

Also, If you are familiar with the hyperbolic functions then we can proceed as follows:

# y = (e^x+e^(-x))/4 #

# \ \ = 1/2 * (e^x+e^(-x))/2 #

# \ \ = 1/2coshx #

and so:

# dy/dx = 1/2sinhx #