# How do you find the derivative of #y=ln(5x)#?

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A student comfortable with the natural logarithm function and its properties might think of this:

One could reason as follows:

But

Therefore,

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#y'=1/x#

**Explanation**

Suppose,

#y=ln(b(x))# then using Chain Rule,

#y'=1/(b(x))*(b(x))'# Similarly following for the above function yields,

#y'=1/(5x)*(5x)'#

#y'=1/(5x)*5#

#y'=1/x#

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Using the Chain Rule you'll get:

(Derive

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