Question

How do you find the derivative of `y=(ln2x)^2`?

Answer 1

You can do it like this:

Explanation:

`y=(ln2x)^2`

You need to apply the chain rule successively:

`dy/dx=2(ln2x)^(1)xx1/(cancel(2)x)xxcancel(2)`

`dy/dx=(2ln2x)/x`