How do you find the derivative of $y = {(ln 2 x)}^{2}$ $y=(ln2x)^2$ ?

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Answer 1 · 2016-04-03T16:21:16

You can do it like this:

$y = {(ln 2 x)}^{2}$ $y=(ln2x)^2$

You need to apply the chain rule successively:

$dy/dx=2(ln2x)^(1)xx1/(cancel(2)x)xxcancel(2)$

$dy/dx=(2ln2x)/x$

How do you find the derivative of y=(ln2x)^2y=(ln2x)2y=(ln2x)^2?