# How do you find the derivative of y=(ln2x)^2?

Apr 3, 2016

You can do it like this:

#### Explanation:

$y = {\left(\ln 2 x\right)}^{2}$

You need to apply the chain rule successively:

$\frac{\mathrm{dy}}{\mathrm{dx}} = 2 {\left(\ln 2 x\right)}^{1} \times \frac{1}{\cancel{2} x} \times \cancel{2}$

$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{2 \ln 2 x}{x}$