Question

How do you find the derivative of `y =sqrt(x+1)`?

Answer 1

By rewriting the square-root as the 1/2-power,

`y=(x+1)^{1/2}`

By Chain Rule,

`y'=1/2(x+1)^{1/2-1}cdot(x-1)'`

`=1/2(x+1)^{-1/2}cdot 1`

`=1/{2sqrt{x+1]}`