Question

How do you find the derivative of `y=sqrtx/x`?

Answer 1

`dy/dx=-1/2x^(-3/2)`

Explanation:

Using the power rule:

`dy/dx = d/dxsqrt(x)/x`

`=d/dxx^(1/2)/x^1`

`=d/dxx^(1/2-1)`

`=d/dxx^(-1/2)`

`=-1/2x^(-1/2-1)`

`=-1/2x^(-3/2)`