Question

How do you find the derivative of `y = (x^2+4x+3)/x^.5`?

Answer 1

If this is `y = (x^2+4x+3)/x^0.5`, we can use the quotient rule or rewrite as follows.

Explanation:

`y = (x^2+4x+3)/x^0.5 = x^2/x^0.5 +(4x)/x^0.5+3/x^0.5`

`= x^1.5 +4x^0.5 +3x^-0.5`

So

`y' = 1.5x^0.5 +2x^-0.5 +1.5 x^-1.5`