Question

How do you find the derivative of `z = e^[(x^2)+xy]`?

Answer 1

`z'=(2x+y)e^[(x^2)+xy] or z'=xe^[(x^2)+xy]`

Explanation:

`z = e^[(x^2)+xy]`

The derivative of `z` in terms of `x` is:

`(e^u)'=u'*e^u`
`u=(x^2)+xy`
`u'=2x+y`

`z'=(2x+y)e^[(x^2)+xy]`

In terms of y:

`z'=xe^[(x^2)+xy]`