Question

How do you find the derivative using the quotient and chain rule of `f(x) = [(3x^2 + 1)^(1/3) - 5]^2 / [5x^2 + 4]^(1/2)`?

Answer 1

The formula we Need is: `(u'v-uv')/v^2`

Explanation:

`v'=1/2*(5x^2+4)^(-1/2)*10*x`
and
`u'=2*((3x^2+1)^(1/3)-5)*(1/3)*(3*x^2+1)^(-2/3)*6x`