How do you find the determinant of #((1, 1, 1,), (1, 2, 3), (3, 2, 1))#?

1 Answer
Alan P.
Feb 9, 2016

#|(1,1,1),(1,2,3),(3,2,1)| = 0#

Explanation:

#|(color(red)(1),color(blue)(1),color(green)(1)),(1,2,3),(3,2,1)|#

#color(white)("XXXXXX")=color(red)(1xx|(2,3),(2,1)|)-color(blue)(1xx|(1,3),(3,1)|+color(green)(1xx|(1,2),(3,2)|#

#color(white)("XXXXXX")=(color(red)(2xx1-3xx2)) - (color(blue)(1xx1-3xx3))+(color(green)(1xx2-2xx3))#

#color(white)("XXXXXX")=color(red)(-4)-(color(blue)(-8))+color(green)(-4)#

#color(white)("XXXXXX")=0#

Related questions
See all questions in Determinant of a Square Matrix
Impact of this question
1587 views around the world
You can reuse this answer
Creative Commons License