How do you find the determinant of ((2, -2, 2), (1, 2, 4), (3, 0, 5))?

1 Answer
May 16, 2016

I found -6

Explanation:

I would add the first line to the second to get:
((2,-2,2),(3,0,6),(3,0,5))
I would then cancel the first line and second row maintaining the intersection corresponding to -2 and a minus sign corresponding to its position in the sequence:
((+,-,+),(-,+,-),(+,-,+))
getting:
color(red)(-)(color(blue)(-2))((3,6),(3,5))
or:
2((3,6),(3,5))
and a determinant of:
2[(3*5)-(6*3)]=-6