How do you find the determinant of $((3, 0, -1), (4, 6, 2), (8, -2, 3))$ ?

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Answer 1 · 2016-03-11T17:15:43

$det=122$

$D=3|(6,2),(-2,3)|-0|(4,2),(8,3)|+(-1)|(4,6),(8,-2)|$

$=3(18-(-4))-0 -1(-8-48)->$ Use Cramer's Rule $|(r,s),(t,u)|=ru-st$

$=3(22)-1(-56)$

$=66+56$

$det=122$

How do you find the determinant of ((3, 0, -1), (4, 6, 2), (8, -2, 3))((3, 0, -1), (4, 6, 2), (8, -2, 3))?