# How do you find the determinant of ((3, 0, -1), (4, 6, 2), (8, -2, 3))?

Mar 11, 2016

$\det = 122$

#### Explanation:

$D = 3 | \left(6 , 2\right) , \left(- 2 , 3\right) | - 0 | \left(4 , 2\right) , \left(8 , 3\right) | + \left(- 1\right) | \left(4 , 6\right) , \left(8 , - 2\right) |$

$= 3 \left(18 - \left(- 4\right)\right) - 0 - 1 \left(- 8 - 48\right) \to$Use Cramer's Rule $| \left(r , s\right) , \left(t , u\right) | = r u - s t$

$= 3 \left(22\right) - 1 \left(- 56\right)$

$= 66 + 56$

$\det = 122$