How do you find the determinant of #|(4,6,7),(3,-2,-4), (1,1,1)|#?

1 Answer
Aug 3, 2017

Answer:

The Rule of Sarrus! -> #det(A) = 1#

Explanation:

Order three determinants follow The Rule of Sarrus . Consider a matrix

#A = |(a_1,a_2,a_3),(a_4,a_5,a_6), (a_7,a_8,a_9)|#

The Rule of Sarrus says:

#det(A) = |A| = a_1 a_5 a_9 + a_2 a_6 a_7 + a_3 a_4 a_8 - a_3 a_5 a_7 - a_6 a_8 a_1 - a_9 a_4 a_2#

These pictures may help in understanding what this rule does:

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Positive sign:
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Negative sign:
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In your case:

#|A| = -8 - 24 + 21 + 14 + 16 - 18 = 1#