How do you find the determinant of #((5, 3, 1, 2), (0, 1, -1, 3), (2, 7, -4, 1), (3, 3, 5, -2))#?

1 Answer
May 3, 2016

Answer:

#434#

Explanation:

#((5,color(teal)(3),color(orange)(1),color(turquoise)(2)),(0,color(teal)(1),color(orange)(-1),color(turquoise)(3)),(2,color(teal)(7),color(orange)(-4),color(turquoise)(1)),(3,color(teal)(3),color(orange)(5),color(turquoise)(-2)))=#
#-># column3 #+# column2 #-># column3
#-># column4 #-3*# column2 #-># column4

#=((5,color(gold)(3),4,-7),(color(gold)(0),color(blue)(1),color(gold)(0),color(gold)(0)),(2,color(gold)(7),3,-20),(3,color(gold)(3),8,-11))#

#=1*(-1)^(2+2)*((5,4,-7),(2,3,-20),(3,8,-11))#

#=-165-240-112-(-63-800-88)#
#=-517+951=434#