# How do you find the differential dy of the function y=xsinx?

Feb 24, 2017

$\mathrm{dy} = \left(\sin x + x \cos x\right) \mathrm{dx}$

#### Explanation:

First, we need to differentiate this function using the product rule:

$\frac{\mathrm{dy}}{\mathrm{dx}} = \sin x + x \cos x$

Now we can multiply the derivative by $\mathrm{dx}$ to get $\mathrm{dy}$ on its own:

$\mathrm{dy} = \left(\sin x + x \cos x\right) \mathrm{dx}$