Question

How do you find the discriminant `2x^2+3x-9=0`?

Answer 1

Discriminant is `81`

Explanation:

`2x^2+3x-9=0`
Comparing with general quadratic equation `ax^2+bx+c=0` we get `a=2 ,b= 3 , c= -9`
Disciminant is `D=b^2-4ac or D= 3^2 -4 * 2* (-9) = 9 +72 = 81`

If `D >0` , there is 2 real solution.
If `D =0` , there is 1 real solution.
If `D<0` , there is no real solution , roots are imaginary.
Discriminant is `81` [Ans]