# How do you find the discriminant and how many and what type of solutions does 3x^2 – 6x + 3 = 0 have?

Apr 29, 2015

Given a quadratic equation in the general form: $a {x}^{2} + b x + c = 0$
The discriminant is:
$\Delta = {b}^{2} - 4 a c$
$a = 3$
$b = - 6$
$c = 3$
So: $\Delta = 36 - 36 = 0$
Remember that:
$\Delta > 0$ two real separate solutions;
$\Delta = 0$ two real coincident solutions;
$\Delta < 0$ No real solutions.