# How do you find the discriminant and how many solutions does 2a^2 + 4a - 6 = 0 have?

Apr 29, 2015

Given a quadratic equation in the general form: $u {a}^{2} + v a + t = 0$
The discriminant is:
$\Delta = {v}^{2} - 4 u t$
$u = 2$
$v = 4$
$t = - 6$
So: $\Delta = \ldots .$
$\Delta > 0$ two real separate solutions;
$\Delta = 0$ two real coincident solutions (the same value counted twice);
$\Delta < 0$ No real solutions.