How do you find the discriminant and how many solutions does 3x^2 - 5x + 4 = 03x25x+4=0 have?

1 Answer
May 3, 2015

3x^2-5x+4=03x25x+4=0

For a quadratic in the form
ax^2+bx+c=0ax2+bx+c=0
the discriminant is
Delta = b^2-4ac
where
Delta {(<0 rarr "no solutions"),(=0 rarr 1 "solution"),(>0 rarr 2 "solutions"):}

Delta = b^2-4ac

= (-5)^2 -4(3)(4)

=25- 48 = -23

<0

The given quadratic equation has no solutions.