How do you find the discriminant and how many solutions does #5w^2-2w+4=0 # have?

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Answer 1 · 2018-07-25T18:10:38

#b^2-4ac=-76#, two complex conjugate roots

The given quadratic equation:

#5w^2-2w+4=0#

Comparing the above equation with the standard quadratic equation: #ax^2+bx+c=0# we get

#a=5, b=-2# & #c=4#

hence the discriminant #b^2-4ac# of given quadratic equation is given as

#b^2-4ac=(-2)^2-4(5)(4)#

#=-76< 0#

#because b^2-4ac < 0# hence given quadratic equation has two conjugate complex roots.