# How do you find the discriminant and how many solutions does 7c^2 + 8c + 1 = 0 have?

May 4, 2015

There is another way.

$7 {c}^{2} + 8 c + 1 = 0.$

No need to solve this type of quadratic equation. Use shortcut.
Since a - b + c = 0, there are 2 real roots: (-1) and (-c/a = -1/7).

Reminder of shortcut:

a. When a + b + c = 0, one real root is (1) and the other is (c/a).

b. When a - b + c = 0, one real root is (-1) and the other is (-c/a).