# How do you find the discriminant and how many solutions does m^2-8m=-14 have?

First, add 14 to both sides to get ${m}^{2} - 8 m + 14 = 0$.
This is in standard form like $a {m}^{2} + b m + c = 0$, with $a = 1$, $b = - 8$ and $c = 14$.
The discriminant is ${b}^{2} - 4 a c = {\left(- 8\right)}^{2} - 4 \cdot 1 \cdot 14 = 64 - 56 = 8$.