Question

How do you find the discriminant and how many solutions does `r^2=3r+0` have?

Answer 1

Your equation, written as `r^2-3r=0` is in the form: `ax^2+bx+c=0`
Where:
`a=1`
`b=-3`
`c=0`
The discriminant is:
`Delta=b^2-4ac=9-4(1*0)=9>0`
Now, if:
1] `Delta>0` you have 2 distinct Real solutions;
2] `Delta=0` you have two Real coincident solutions;
3] `Delta<0` you have no Real solutions.