# How do you find the domain and range for f(x)=sqrt(4-2x)?

Mar 4, 2018

$\left(- \infty , 2\right]$

#### Explanation:

You may know that the content in a square route should be equal to or more than 0.
So, first we suppose that: $4 - 2 x \ge 0$
$4 - 2 x \ge 0$
$4 \ge 2 x$
$2 \ge x$
$x \le 2$
$\left(- \infty , 2\right]$
so the x can take values from 2 and less than 2 ,for example: 1,0,...,$- \infty$