How do you find the domain and range of #5/(4-9x)#?

1 Answer
Jun 30, 2016

Answer:

The domain is made of all real numbers except #4/9#
The range is made of all numbers except 0

Explanation:

you can find the domain by excluding x values that make null the denominator:

#4-9x!=0#

that's

#x!=4/9#

Let's find the inverse function through these simple steps:

let

#y=f(x)=5/(4-9x)#

#4y-9xy=5 and x!=4/9#

#9xy=4y-5#

#x=(4y-5)/(9y)#

so the range of y is the domain:

#y!=0#