How do you find the domain and range of F(x) = -2(x + 3)² - 5?

1 Answer
Jun 30, 2018

x inRR,y in(-oo,-5]

Explanation:

"this is a polynomial of degree 2 and is defined for all "
"real values of "x

"domain is "x inRR

"to find the range we require the vertex and if maximum"
"or minimum turning point"

"the equation of a parabola in "color(blue)"vertex form" is.

•color(white)(x)y=a(x-h)^2+k

"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"

f(x)=-2(x+3)^2-5" is in this form"

"with "(h,k)=(-3,-5)" and "a=-2

"since " a <0" then maximum turning point"

"range is "y in(-oo,-5]
graph{-2(x+3)^2-5 [-28.46, 28.5, -14.22, 14.25]}