How do you find the domain and range of #f(x) =2sinx#?

1 Answer

Answer:

Domain : #-oo<=x<=+oo#
Range: #-2<=f(x)<=2#

Explanation:

The value of x in the equation #y=2 sin x# can any real number along the x-axis so the domain is #-oo<=x<=+oo#

The value of f(x) in the equation #y=2 sin x# can only take values from -2 to +2. The range is #-2<=f(x)<=2#

the graph of #f(x)=2 sinx # at close up
graph{y=2 sin x[-5,5,-2.5,2.5]}

the graph of #f(x)=2 sinx # at somewhere away
graph{y=2 sin x[-20,20,-10,10]}

God bless...I hope the explanation is useful.