How do you find the domain and range of f(x) = ln(4 - 2x)?

Oct 9, 2017

$x \in \left(- \infty , 2\right)$ and $f \left(x\right) \in \left(- \infty , + \infty\right)$

Explanation:

In this question we are going to apply conditions.

If we have a logarithmic function as $\ln a$ we know that $a > 0$.

When we apply it to your question-->

$\left(4 - 2 x\right) > 0$

$\left(- 2 x\right) > \left(- 4\right)$

$2 x < 4$

$x < 2$ which in interval notation is $x \in \left(- \infty , 2\right)$
This is our domain.

Now for the range --.>

The range would be all real numbers ,i.e, $f \left(x\right) \in \left(- \infty , + \infty\right)$