# How do you find the domain and range of #f(x)=sqrt(2x^2-5x+2)#?

##### 1 Answer

See below.

#### Explanation:

If we are going to stay in the realm of real numbers, then the expression inside the radical (This is called the radicand) must be

Factoring to find roots. (This gives us a starting position ):

We can actually cheat a bit here. Notice the coefficient of

So our domain is:

Minimum value of function is

Maximum value:

Since

So range is:

Graph of

graph{sqrt(2x^2-5x+2) [-58.5, 58.57, -29.24, 29.23]}