# How do you find the domain and range of #f(x)=sqrt (x+7)/(x^2+7)#?

##### 1 Answer

Dec 25, 2017

domain

#### Explanation:

**Suppose,y= #f(x)=sqrt(x+7)/(x^2+7)#**

*If*#x<(-7), # the mentioned equation can not be definable.

*Hence,Domain #RR=color(red){{x:x inRR,x>=(-7)}#*

*For the value of domain set,range of the equation will be greater than or equal #0#*

*So,Range