# How do you find the domain and range of g(x) = 1-2x^2?

Mar 7, 2017

$- \infty < x < + \infty$
Since ${x}^{2} \ge 0 \to - 2 {x}^{2} \le 0$:
$\to 1 - 2 {x}^{2} \le 1$ (equal when $x = 0$)
So the range is $- \infty < g \left(x\right) \le 1$