How do you find the domain and range of #h(t) = 1/(t^2)#?

1 Answer
Cri007
May 17, 2017

See below.

Explanation:

The domain of a function relates to its #x# value, or in this case, #t#. The range is the function, or #h(t)#.

#1/0# is undefined, which happens when #t=0#, so the domain does not include zero.

Since the denominator is squared, the range of the function will never be negative.

As #t# approaches infinity, #h(t)# approaches #0#.
As #t# approaches zero, #h(t)# also approaches #oo#.

Thus, the domain is #(oo,0)uu(0,oo)#, and the range is #(0,oo)#.

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