# How do you find the domain and range of h(t) =sqrt(3t+5) ?

Sep 14, 2016

#### Answer:

Everything under the root should be non-negative or $\ge 0$

#### Explanation:

$\to 3 t + 5 \ge 0 \to 3 t \ge - 5 \to t \ge - \frac{3}{5}$

There are no restrictions for $t$ getting larger, so domain $\left[- \frac{3}{5.} \infty\right)$

As the lowest value of the argument can reach $0$ the range is $\left[0 , \infty\right)$