Question

How do you find the domain and range of `h(t) =sqrt(3t+5)`?

Answer 1

Everything under the root should be non-negative or `>=0`

Explanation:

`->3t+5>=0->3t>=-5->t>=-3/5`

There are no restrictions for `t` getting larger, so domain `[-3/5. oo)`

As the lowest value of the argument can reach `0` the range is `[0,oo)`