# How do you find the domain and range of #h(x)=-sqrt(x+3)#?

##### 1 Answer

Jan 22, 2018

#### Explanation:

#x+3>=0#

#rArrx>=-3#

#rArr"domain is "x inRR,x>=-3#

#rArr[-3,+oo)larrcolor(blue)"in interval notation"#

#sqrt(x+3)" has a range "[0,+oo)#

#"but "-sqrt(x+3)" is "sqrt(x+3)" reflected in the x-axis"#

#rArr"range is "[0,-oo)#

graph{-sqrt(x+3) [-10, 10, -5, 5]}