How do you find the domain and range of #h(x) = (x - 2)^2 + 2#?
1 Answer
Jul 26, 2018
Explanation:
#"This is a polynomial of degree 2 and is well defined for all"#
#"real values of "x#
#"domain is "x inRR#
#(-oo,+oo)larr color(blue)"in interval notation"#
#"To obtain the range we require the vertex and whether"#
#"it is a max/min turning point"#
#"The equation of a parabola in "color(blue)"vertex form"# is.
#•color(white)(x)y=a(x-h)^2+k#
#"where "(h,k)" are the coordinates of the vertex and a is"#
#"a multiplier"#
#y=(x-2)^2+2" is in this form"#
#color(magenta)"vertex "=(2,2)#
#"Since "a>0" then minimum turning point "uuu#
#"range is "y in[2,+oo)#
graph{(x-2)^2+2 [-10, 10, -5, 5]}