Question

How do you find the domain and range of `h(x)= x^2 - 5`?

Answer 1

Domain : `x` may have any value

Explanation:

Range:Since `x^2` is always `>=0` the function will always be `>=-5`.
There is no upper limit.

So:
Domain: `-oo < x<+oo`
Range `-5<=h(x)<+oo`