# How do you find the domain and range of h(x)= x^2 - 5?

Jul 23, 2015

Domain : $x$ may have any value

#### Explanation:

Range:Since ${x}^{2}$ is always $\ge 0$ the function will always be $\ge - 5$.
There is no upper limit.

So:
Domain: $- \infty < x < + \infty$
Range $- 5 \le h \left(x\right) < + \infty$