How do you find the domain and range of #P(r)= 3/(sqrtr)#?

1 Answer
Jun 29, 2017

Answer:

Domain 0f #P(r)# is the set of all positive real numbers i.e.
#+R#.
Range 0f #P(r)# is the set of all positive real numbers i.e.
#+R#.

Explanation:

We know that anything divided by 0 is undefined or infinity and square root of negative numbers is not real . So we need to ensure that value of r is not equal to 0 or any negative numbers since it would not result in real values.

Therefore, Domain 0f #P(r)# is the set of all positive real numbers i.e.
#+R#.
Since the denominator is positive (as accepts only positive values) hence the function would always return a positive real number.

Therefore, Range 0f #P(r)# is the set of all positive real numbers i.e.
#+R#.