Question

How do you find the domain and range of `sqrt(5x-3) + 4`?

Answer 1

The domain is limited by the rule that the argument of a square root must be non-negative.

Explanation:

Domain:
`5x-3>=0->x>=3/5` (there is no upper limit)

Range:
The lower limit of `sqrt(5x-3)` is `0`,
so the range of the function as a whole is `y>=4` (with again no upper limit)
graph{sqrt(5x-3)+4 [-7.57, 24.47, -1.98, 14.05]}