How do you find the domain and range of #sqrt(5x-3) + 4#?

1 Answer
Dec 23, 2016

Answer:

The domain is limited by the rule that the argument of a square root must be non-negative.

Explanation:

Domain:
#5x-3>=0->x>=3/5# (there is no upper limit)

Range:
The lower limit of #sqrt(5x-3)# is #0#,
so the range of the function as a whole is #y>=4# (with again no upper limit)
graph{sqrt(5x-3)+4 [-7.57, 24.47, -1.98, 14.05]}