How do you find the domain and range of #sqrt1-sqrtx+7 #?

1 Answer
Jun 30, 2017

Answer:

Domain: #x >= 0#. In interval notation : # [0,oo)#
Range: #y <=8# In interval notation : # (-oo,8]#

Explanation:

#y= sqrt(1) - sqrt(x) +7 or y= 8-sqrt(x)#

Domain: Under root should be #>=0 :. x>= 0# ,

Domain: #x >= 0#. In interval notation : # [0,oo)#

Range: Max #y=8# , Minimum: #y = -oo#

Range: #y <=8# In interval notation : # (-oo,8]#

graph{8-x^0.5 [-160, 160, -80, 80]}