How do you find the domain and range of tan^-1(x)tan1(x)?

1 Answer
Jul 30, 2018

The domain is x in RR. The range is y in (-pi/2, pi/2)

Explanation:

Before let's define the domain and range of

y=tanx

The domain of the function y=tan x is

x in (-pi/2,pi/2)

The range of the function y=tan x is

y in (-oo, +oo)

The function y=tan^-1x is symmetric to the function y=tanx with respect the line y=x

Therefore, the domain is x in RR

and the range is y in (-pi/2, pi/2)

graph{(y-tanx)(y-arctanx)(y-x)=0 [-5.014, 9.034, -3.367, 3.66]}