How do you find the domain and range of #x^52x^3+1#?
1 Answer
Answer:
The domain and range are both the whole of
Explanation:
Any polynomial
For any polynomial
So if

As
#x# gets large and negative#f(x)# gets large and negative. 
As
#x# gets large and positive#f(x)# gets large and positive.
Polynomials are also continuous (no breaks in the graph).
As a result, the graph of
Hence the range is also the whole of
graph{(x^52x^3+1y)(y  3.2) = 0 [10, 10, 5, 5]}