# How do you find the domain and range of #Y=(2x-1)^(1/2)#?

##### 1 Answer

Jul 23, 2017

The domain is

The range is

#### Explanation:

Our function is

What's under the square root sign is

Therefore,

The domain is

The minimum value of

The range is

graph{sqrt(2x-1) [-6.244, 6.243, -3.12, 3.123]}