# How do you find the domain and range of y=-3x^2-x+1?

Jun 4, 2018

$x \in m a t h \boldsymbol{R}$ and $y \le \frac{13}{12}$

#### Explanation:

It is clear that we can plug in all real number in our function
$y = - 3 {x}^{2} - x + 1$
we get be diiferentiating with respect to $x$
$y ' \left(x\right) = - 6 x - 1$
$y ' ' \left(x\right) = - 6$
so we get
$y \left(- \frac{1}{6}\right) = \frac{13}{12}$
and we get
$y \le \frac{13}{12}$