How do you find the domain and range of #y = - sqrt(1 - x)#?

1 Answer
May 12, 2018

Answer:

Domain#in(-∞,1] #
Range #in(-∞,0]#

Explanation:

For the domain part, clearly the part inside the square root must be positive or zero that is
#1-x >=0#
#x>=1#
So domain #in( -∞, 1]#
Clearly as the value of x approaches -∞ that of y also approaches -∞
And if x=1, y=0
Therefore domain#in(-∞,1] #
Range #in(-∞,0]#

Hope it helps!!