Question

How do you find the domain and range of `y = sqrt(2-x)`?

Answer 1

Refer to explanation

Explanation:

The domain for `y` is all the real values of `x` for which

`2-x>=0=>2>=x` Hence `D(f)=(-oo,2]`

Now for the range we notice that

`y=sqrt(2-x)>=0` hence `R(f)=[0,+oo)`