# How do you find the domain of (3x-6)/ (sqrt(2x+1) - 3)?

$\left(2 x + 1\right) > 0 \to 2 x > - 1 \to x > - \frac{1}{2}$
The domain of $x$ is $\left(- \frac{1}{2} , + \infty\right)$
Check: $\mathmr{if} x = 1 \to \left(2 x + 1\right) = 3 > 0$