# How do you find the domain of #f(x)=(3x-1)/(x^2+9)#?

##### 2 Answers

Apr 28, 2018

#### Answer:

The domain of

#### Explanation:

The function is

Therefore,

The domain of

graph{(3x-1)/(x^2+9) [-7.02, 7.03, -3.51, 3.51]}

Apr 28, 2018

#### Answer:

#### Explanation:

#"the denominator of "f(x)" cannot be zero as this would"#

#"make "f(x)" undefined"#

#x^2+9" is always positive for all "x inRR#

#rArr"domain "x in(-oo,oo)#

graph{(3x-1)/(x^2+9) [-10, 10, -5, 5]}