How do you find the domain of #f(x) = sqr(25 - x^2)#?

1 Answer

Answer:

Domain: [-5, 5]
Range: [0, 5]

Explanation:

The given equation is #f(x)=sqrt(25-x^2)# and any value of x>5 will make the radicand negative. Also any value of x<-5 will make the radicand negative, therefore the domain is #-5<=x<=5#.

The range is found by checking the value of f(x) at #x=+-5# and #x=0#. When #x=+-5# the value of #f(x)=0# and when #x=0#, the value of #f(x)=5#. We can conclude that Range is #0<=f(x)<=5#

God bless....I hope the explanation is useful.